represent this polar equation: r=a(1+cosine of theta) in a cartesian form

Question

anonymous · Answer

use x^2 + y^2  = r^2 ans tan theta = sin theta / cos theta = y / x

anonymous · Answer

$\large r=a(1+cos\theta) $

square both sides to get 

$\large r^2=a^2(1+cos\theta)^2 $

then expand that right side then you can make substitutions using these relations:

$\large x=rcos\theta $ and $\large y=rsin\theta $ 
and also 
$\large x^2+y^2=r^2 $

anonymous · Answer

@dpalnc...i got stuck. the degree of the equation i'm getting is scary. very scary. can u help me out with the final ans so i could compare

anonymous · Answer

@Aparna2...yea i started with dat already but then it got very ugly along the line with an equation with very high degrees

anonymous · Answer

It is just some algebra, nothing higher than quadratic.....