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Mathematics 9 Online
OpenStudy (mathlegend):

Evaluating Expressions

OpenStudy (mathlegend):

\[\ 5(\frac{ x }{ y})-x\]

OpenStudy (mathlegend):

x = 6 y = 2/3

OpenStudy (turingtest):

replace the x's in your expression with 6 and the y with 2/3 what part is tripping you up?

OpenStudy (mathlegend):

The 'y' how can a fraction be the denominator of another fraction?

OpenStudy (turingtest):

\[\frac a{\frac bc}=a\cdot\frac cb\]

OpenStudy (turingtest):

so dividing by a fraction is the same as multiplying by its reciprocal

OpenStudy (mathlegend):

5 * 3/2?

OpenStudy (mathlegend):

@hartnn do you understand this? What he said didn't help.

hartnn (hartnn):

what he said was correct \(\huge \frac{a}{\frac{b}{c}}=a.\frac{c}{b}\) so now u have 5*(x/y) where x=6 , y= 2/3 so \(\huge \frac{5}{\frac{2}{3}}6=5.\frac{3}{2}.6\) make sense ?

OpenStudy (turingtest):

@hartnn LaTeX note \cdot\[\cdot\] (puts the dots in the middle ;) )

OpenStudy (mathlegend):

why do you put 5/2/3?

hartnn (hartnn):

\(5 \cdot 6\) :) thanks .

OpenStudy (mathlegend):

The 5 wasn't apart of the fraction

hartnn (hartnn):

because the question had 5x/y

hartnn (hartnn):

5(x/y) = 5x/y = (5x) / y

OpenStudy (mathlegend):

Yeah but that answer gives you 45

OpenStudy (mathlegend):

My teacher said the answer was 39

OpenStudy (mathlegend):

@Hero can you help?

hero (hero):

No one helped you already?

OpenStudy (mathlegend):

Yes, but I don't understand why they are doing what they are doing

OpenStudy (mathlegend):

I'm trying to figure out why everyone puts 5 in the numerator but it is not like that

OpenStudy (mathlegend):

its a mixed number

hartnn (hartnn):

because u are yet to subtract 6 u got 45, 45-6 = 39 ...

hartnn (hartnn):

isn't 5 in numerator ?

OpenStudy (mathlegend):

In the original problem it is not

hartnn (hartnn):

where is 5 according to u ?

OpenStudy (mathlegend):

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