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OpenStudy (mathlegend):
\[\ 5(\frac{ x }{ y})-x\]
OpenStudy (mathlegend):
x = 6
y = 2/3
OpenStudy (turingtest):
replace the x's in your expression with 6 and the y with 2/3
what part is tripping you up?
OpenStudy (mathlegend):
The 'y' how can a fraction be the denominator of another fraction?
OpenStudy (turingtest):
\[\frac a{\frac bc}=a\cdot\frac cb\]
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OpenStudy (turingtest):
so dividing by a fraction is the same as multiplying by its reciprocal
OpenStudy (mathlegend):
5 * 3/2?
OpenStudy (mathlegend):
@hartnn do you understand this? What he said didn't help.
hartnn (hartnn):
what he said was correct
\(\huge \frac{a}{\frac{b}{c}}=a.\frac{c}{b}\)
so now u have 5*(x/y) where x=6 , y= 2/3
so
\(\huge \frac{5}{\frac{2}{3}}6=5.\frac{3}{2}.6\)
make sense ?
OpenStudy (turingtest):
@hartnn LaTeX note
\cdot\[\cdot\] (puts the dots in the middle ;) )
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OpenStudy (mathlegend):
why do you put 5/2/3?
hartnn (hartnn):
\(5 \cdot 6\)
:) thanks .
OpenStudy (mathlegend):
The 5 wasn't apart of the fraction
hartnn (hartnn):
because the question had 5x/y
hartnn (hartnn):
5(x/y) = 5x/y = (5x) / y
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OpenStudy (mathlegend):
Yeah but that answer gives you 45
OpenStudy (mathlegend):
My teacher said the answer was 39
OpenStudy (mathlegend):
@Hero can you help?
hero (hero):
No one helped you already?
OpenStudy (mathlegend):
Yes, but I don't understand why they are doing what they are doing
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OpenStudy (mathlegend):
I'm trying to figure out why everyone puts 5 in the numerator but it is not like that
OpenStudy (mathlegend):
its a mixed number
hartnn (hartnn):
because u are yet to subtract 6
u got 45,
45-6 = 39 ...
hartnn (hartnn):
isn't 5 in numerator ?
OpenStudy (mathlegend):
In the original problem it is not
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