Mathematics
10 Online
OpenStudy (anonymous):
factor 21x^2-49x-9x-21
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OpenStudy (anonymous):
idk how i got 7x(3x-7) 3(3x-7) and i know its wrong
hartnn (hartnn):
is the original problem
21x^2-58x-21 ?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
hartnn (hartnn):
right,so thats 21x^2-40x-21=0
right ?
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OpenStudy (anonymous):
yeah and then the product of 21 and -21 is -441 and then 40 so the two numbers are -49 and 9
hartnn (hartnn):
that is correct,
see above u have written -49x - 9x
instead of what u got now as
-49x+9x
OpenStudy (anonymous):
oooh i see wow
hartnn (hartnn):
now whats common from first 2 terms in
21x^2-49x-9x-21 =0?
OpenStudy (anonymous):
7x
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OpenStudy (anonymous):
i got the answer :P -3/7 and 7/3
hartnn (hartnn):
yup, correct.
OpenStudy (anonymous):
im having problems with another equation
hartnn (hartnn):
which ?
OpenStudy (anonymous):
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OpenStudy (anonymous):
i got to the point 9 + or - sqrt of 1 all over 4
hartnn (hartnn):
9 from where ?
hartnn (hartnn):
Compare your quadratic equation with \(ax^2+bx+c=0\)
find a,b,c
then the two rots of x are:
\(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
OpenStudy (anonymous):
yeah b is 9
hartnn (hartnn):
nopes, b is -4
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OpenStudy (anonymous):
oh wait nooo i gave you the wrong equation! no wonder
hartnn (hartnn):
lol :P
OpenStudy (anonymous):
hartnn (hartnn):
still b is -9
OpenStudy (anonymous):
but in that equation it says -b so -(-9) is 9
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OpenStudy (anonymous):
inside i did put put -9^2 = 81
hartnn (hartnn):
yes, u are correct
\(\huge\frac{9 \pm \sqrt{1}}{4}=\frac{10}{4},\frac{8}{4}\)
OpenStudy (anonymous):
wait you are just adding and subtracting the 1?
OpenStudy (anonymous):
obviously lol never mind i feel stupid
hartnn (hartnn):
got it now ?
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OpenStudy (anonymous):
yes, it was a stupid moment :P
OpenStudy (anonymous):
ok i did another one and i got 4+-sqrt of 28 all over 2 @hartnn
hartnn (hartnn):
question ?
OpenStudy (anonymous):
its the first one that sent you
OpenStudy (anonymous):
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hartnn (hartnn):
thats correct :)
OpenStudy (anonymous):
but how do i factor it?
hartnn (hartnn):
do u want to factor or do u want to use quadratic formula?
anyways its not factorable....
OpenStudy (anonymous):
so what would be the answer?
OpenStudy (anonymous):
i cant simplify it?
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hartnn (hartnn):
all u can do is
\(2 \pm \sqrt7\)
hartnn (hartnn):
\(\sqrt{28}=2\sqrt7\)
OpenStudy (anonymous):
how does that equal to that
hartnn (hartnn):
\(\sqrt{28}=\sqrt{7*4}=\sqrt{7}\sqrt{4}=2\sqrt{7}\)
OpenStudy (anonymous):
got it
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OpenStudy (anonymous):
you are the best!
hartnn (hartnn):
lol. glad to hear that :)
u too are awesome ;)
OpenStudy (anonymous):
lol thank you, well i gotta keep doing this stupid hw
hartnn (hartnn):
best of luck for that.