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OpenStudy (anonymous):
whats the answer for 1 srqt of 1+260pi^2 all over 2 pi
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OpenStudy (anonymous):
1 + srqt of 1+260pi^2 all over 2 pi
OpenStudy (turingtest):
you want to simplify\[\LARGE\frac1{\sqrt{1+260\pi^2}}\over2\pi\]correct?
OpenStudy (anonymous):
idk
Directrix (directrix):
Consider clicking on the blue "DRAW" button and manually writing the expression to be simplified. Thanks.
OpenStudy (anonymous):
|dw:1347406508314:dw|
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