A tank containing oil is in the shape of a downward-pointing cone with its vertical axis perpendicular to ground level. (See a graph of the tank here.) In this exercise we will assume that the height of the tank is 10 ft , the circular top of the tank has radius 5 ft, and that the oil inside the tank weighs 56 lb per cubic ft.
How much work does it take to pump oil from the tank to an outlet that is 3 ft above the top of the tank if, prior to pumping, there is only a half-tank of oil? Note: "half-tank" means half the volume in the tank.

Question

A tank containing oil is in the shape of a downward-pointing cone with its vertical axis perpendicular to ground level. (See a graph of the tank here.) In this exercise we will assume that the height of the tank is 10 ft , the circular top of the tank has radius 5 ft, and that the oil inside the tank weighs  56 lb per cubic ft. 
How much work  does it take to pump oil from the tank to an outlet that is 3 ft  above the top of the tank if, prior to pumping, there is only a half-tank of oil?   Note: "half-tank" means half the volume in the tank.

anonymous · Answer

Okay so lets find the volume of this cone
v = 1/3 pi r^2h
785/3 cubic feet is the volume for the full tank 392.5/3 is the volume of the cone half full
130.83 simplified. 
And do you mind helping me help you on the pumping part? like what do you suppose we do?