A jet plane is cruising at 290 m/s when suddenly the pilot turns the engines up to full throttle. After traveling 4.0 km, the jet is moving with a speed of 406 m/s. What is the jet's acceleration (assuming it is constant)

Question

shane_b · Answer

The acceleration can be calculated using the kinematic equation:$$V_f^2=V_i^2+2ad$$Solving for acceleration you get:
$$a=\frac{V_f^2-V_i^2}{2d}$$
Now just plug in the given values:$$a=\frac{(406m/s)^2-(290m/s)^2}{2(4000m)}=10.092m/s^2$$