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find all solutions of the equation on the interval [0,2pie) cos(x+pie/4)-cos(x-pie/4)=1
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you have to use the sum and differnce formula
thats right...\[\cos p-\cos q=-2\sin(\frac{p+q}{2})\sin(\frac{p-q}{2})\]
wrong
it's right..
then cos(x+pie/4)-cos(x-pie/4)= -2sin(x)sin(pie/4) = 1 then sin(x)sin(pie/4) = -1/2
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\[\cos (x+a)-\cos (x-a)=-2\sin(\frac{x+a+x-a}{2})\sin(\frac{x+a-x+a}{2})\]\[\cos (x+a)-\cos (x-a)=-2\sin x\sin(a)\]
can you find answer??
your a is pi/4
finally sinx = -(1/root(2))
so x is (5/4)pi and (7/4)pi
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wow how did you do that
final eq sinx = -(1/root(2)) means that x is over the angle pie
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