Question

How much work (in joules) is done in moving a charge of 2.5 μC a distance of 53 cm along an equipotential at 10 V? I got -2.25e-5 is this correct?

Answer 1

Step I) Identify the quantities, given and asked for, and the relate them to each other.
\[ W = Q \times \delta V \]Here "deltaV" is the change in potential.
Step II) Convert all quantities into their SI units. \[1 \mu C = 10^{-6} C\]\[1cm = 10^{-2} m\]Step III) Substitute and simplify for the answer.

PS: An equipotential surface means that potential does not change along it, so "deltaV" =0.
Thus, the work done must be ??