Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

integration of "e" raise to power "x" square

OpenStudy (lgbasallote):

\[\huge \int e^{x^2}dx\] ???

OpenStudy (lgbasallote):

is that your question?

OpenStudy (anonymous):

yes

OpenStudy (lgbasallote):

..this isn't solveable by natural means...

OpenStudy (anonymous):

well how do i slove it?

OpenStudy (lgbasallote):

numerical analysis was the term if i remember it right

OpenStudy (anonymous):

erf...?

OpenStudy (lgbasallote):

yup. those kinds of functions

OpenStudy (lgbasallote):

only mathematicians solve this. Because they love solving imaginary problems.

OpenStudy (anonymous):

well i am solving an ode and the question is if the given y satisfies it and it contains.. inte^x^2...

OpenStudy (lgbasallote):

they give these stuffs in ode now? are you by any chance from a premier university?

OpenStudy (anonymous):

haha well Ph.D.. i have forgotten the basics.. was just revising

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=integrate+e^%28x^2%29 imaginary error function !!

OpenStudy (lgbasallote):

I am a PhD myself. However, I'm from Liberal Arts...

OpenStudy (anonymous):

@mukushla jinx

OpenStudy (lgbasallote):

i think @gaurangnaware wants to know how to get that erf function....

OpenStudy (anonymous):

lol Algebraic

OpenStudy (anonymous):

use series

OpenStudy (anonymous):

Thanx Mukushla.. go it!

OpenStudy (anonymous):

no problem :)

OpenStudy (anonymous):

series expantion of ex2 is: \[e ^{x ^{2}}=1+\frac{x ^{2}}{1!}+\frac{x ^{4}}{2!}+\frac{x ^{6}}{3!}+....\] this is a uniformly convergent series, so you can integrate it term by term. So just integrate each term to get your answer.

OpenStudy (anonymous):

@gaurangnaware

OpenStudy (anonymous):

@lgbasallote

OpenStudy (anonymous):

or use polar

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!