Question

The absolute value equation |4(x – 1)| = 12 has two solutions.

True
False

Answer 1

false

Answer 2

true

Answer 3

when you have \[| \; f(x) \; | = a\]
then there are automatically two solutions...

however.. if you have \[| \; f(x) \; | = -a\]
then there are no solutions

does that help?

Answer 4

yep...

|4(x-1)|=12

4(x-1)=-12 x<0

4(x-1)=12 x>0

x-1=-3 or x-1=3

x=-2 or 4

Answer 5

so its false :)

Answer 6

it's true...

Answer 7

\[\log_{}\left| x \right| =2\]
how many solutions

Answer 8

all three of us said true and you decided to go with the answer of the only one who said false lol

Answer 9

oh gotcha :) sorry bout that :)

Answer 10

it has only a single soln
since x cannot be -ve in case of log

Answer 11

@Jonask

Answer 12

it can because of the absolute value

Answer 13

I'm blonde lol

Answer 14

that's why they put absolute value on logs...to denote that the argument can't be negative

Answer 15

oh so x can have two hear but at the it becomes +

Answer 16

yes it does

Answer 17

thanks