A stream of water flowing horizontally with a speed of 15 m s–1 gushes out of a tube of cross-sectional area 10–2 m2, and hits a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming it does not rebound?

Question

anonymous · Answer

you have to calculate...how much water is coming out of the tube in 1s

anonymous · Answer

suppose m= mass of water coming out of tube in 1s
force exerted= rate of change of momentum
so force exerted on the wall= mv

anonymous · Answer

This is the Impulse = change-in-momentum (2-nd Newton's l.) question

anonymous · Answer

where v=15 m/s

anonymous · Answer

so force exerted on the wall= mv -m(0)...since water does not rebound