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Physics 21 Online
OpenStudy (ujjwal):

A capacitor of 10 \(\mu\) F charged up to 250 V is connected in parallel with another capacitor of 5 \(\mu\) F charged up to 100 V. The common potential is: a)200V b)300V c)400V d)500V

OpenStudy (anonymous):

200volt

OpenStudy (anonymous):

common potential= (10X250+ 5X100)/(10+5)

OpenStudy (ujjwal):

How?

OpenStudy (anonymous):

expressio for common potential when two charged capacitor are connected is (CaXVa+CbVb)/(Ca+Cb)

OpenStudy (ujjwal):

if in series?

OpenStudy (anonymous):

till i know only parallel if u will get about series dont forgrt me ok bro

OpenStudy (ujjwal):

ok bro!

OpenStudy (anonymous):

i think exp will be same since expression is derived from theory of conservation of charge

OpenStudy (anonymous):

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OpenStudy (ujjwal):

Thanks bro!

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