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A capacitor of 10 \(\mu\) F charged up to 250 V is connected in parallel with another capacitor of 5 \(\mu\) F charged up to 100 V. The common potential is: a)200V b)300V c)400V d)500V
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200volt
common potential= (10X250+ 5X100)/(10+5)
How?
expressio for common potential when two charged capacitor are connected is (CaXVa+CbVb)/(Ca+Cb)
if in series?
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till i know only parallel if u will get about series dont forgrt me ok bro
ok bro!
i think exp will be same since expression is derived from theory of conservation of charge
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Thanks bro!
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