one more question on the same subject. A student guesses the answers to 6 questions on a true-false quiz. Find the probability that the indicated number of guesses are correct: no more than 2 (Hint: No more than 2 means exactly 0 or exactly 1 or exactly 2.)
then your job is to compute exactly 0 right, exactly 1 right, and subtract those from one
of course it is math, that is why she is guessing
i see now
exactly none means all wrong only one way to get all wrong, namely wrong wrong wrong wrong wrong wrong probability is therefore \[\frac{1}{2^6}\] for all wrong
would it be 2/2^6 for 1 right?
one wrong there are 6 possibilities
or one right, same thing
R W W W W W W R W W W W W W R W W W W W W R W W W W W W R W W W W W W R
i think i got my answer, total is gonna be .08-.09
otherwise known as \(\dbinom{6}{1}=6\)
so it is \[1-\frac{1}{2^6}-\frac{6}{2^6}=1-\frac{7}{2^6}\]
Excellent, thanks :)
Join our real-time social learning platform and learn together with your friends!