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OpenStudy (anonymous):
combining functions
x^2-1
------
x^2+x
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OpenStudy (anonymous):
\[\frac{ \left( x-1 \right) \left( x+1 \right)}{ x \left( x+1 \right) }=\frac{ \left( x-1 \right) }{ x }\] something like that
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
no problem :)
OpenStudy (anonymous):
x cannot be -1 or zero
OpenStudy (anonymous):
for x = -1 the answer is zero 0/-1
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OpenStudy (anonymous):
(-1)^2 + (-1) = 0
OpenStudy (anonymous):
yes 0/-1 is 0 >> that it can be x=-1
but x=0 >> f(x) does not exist
OpenStudy (anonymous):
For x is 0 or -1 the original expression has a denominator of 0 (check it)
OpenStudy (anonymous):
I mean for (x-1)/x ><"
OpenStudy (anonymous):
That's what I am telling you, you cannot just cancel the x+1....
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OpenStudy (anonymous):
OK :)
OpenStudy (anonymous):
I do not know the objective of this prob. to find ???
OpenStudy (anonymous):
Or, you can, only if you specify that x is not 0 or -1
OpenStudy (anonymous):
I don't know either, what "combining" means?
OpenStudy (anonymous):
It's a division problem
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OpenStudy (anonymous):
Pinguine has given the answer but you should also specify that the original expression is undefined for x = 0 or -1
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