if the 1st term and common difference of G.P are each equal to x +\[\sqrt{5-x^2} i\]
then the modulus of nterm
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OpenStudy (anonymous):
@ghazi
OpenStudy (anonymous):
common difference of GP???
OpenStudy (anonymous):
is thatsupposed to be common ratio
OpenStudy (anonymous):
both are same \[\sqrt{5-x^2} i\]
OpenStudy (anonymous):
Is "modulus" here meaning "magnitude?"
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OpenStudy (anonymous):
\[a _{n}=ar^{n-1}=(x+\sqrt{5-x^2}i)(x+\sqrt{5-x^2}i)^{n-1}\]
\[=(x+\sqrt{5-x^2}i)^{n}\]
if i is outside the square root
modulus means\[\left| \right|\]
OpenStudy (anonymous):
Yup i is outside
OpenStudy (anonymous):
\[\left| (x+\sqrt{5-x^2}i)^n \right|\]
not sure wat happens to i
OpenStudy (anonymous):
lol...i did nt get u
OpenStudy (anonymous):
from which step
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OpenStudy (anonymous):
The answer shuld be 5^(n/2)
OpenStudy (anonymous):
well i said we have
\[x(x)^{n-1}=x^n\]
where x is that expression
\[(x+\sqrt{5-x^2}i)^n\]
OpenStudy (anonymous):
ok... then
OpenStudy (anonymous):
\[i=\sqrt{-1}\]
so
\[(x+\sqrt{-1}\sqrt{5-x^2})^n\]
OpenStudy (anonymous):
which is
\[(x+\sqrt{x^2-5})^n\]
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