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Mathematics 7 Online
OpenStudy (anonymous):

Each person in this room is mapped to their birthday? is this a relation or a function? and why

OpenStudy (anonymous):

probably not a function because two people would likely share a birthday

OpenStudy (anonymous):

A function relates a set of inputs to a set of outputs. However, there is one important restriction for it to be a function. Each input can only have one output.

OpenStudy (anonymous):

So if the input where people, the output would be their birthdays, is that a valid function?

OpenStudy (anonymous):

yh but if the input has more than one its not a function, so its a relaction?

OpenStudy (anonymous):

But the input is the people. They are all unique, right? If two unique people had the same birthday, would that be a problem? No, because each person(input) relates to exactly one birthday (output)

OpenStudy (anonymous):

ohh soo it is a relation because from every input goes to an output so it is a function right??

OpenStudy (anonymous):

every unique input is mapped to exactly one unique output, so it's a function indeed

OpenStudy (anonymous):

yh thanks man :D can u explain me 1 more please

OpenStudy (anonymous):

nice. a very subjective question wel handled.

OpenStudy (anonymous):

x (the input) is mapped to 2x? what is it

OpenStudy (anonymous):

However, the other way around would NOT work. because the same birthdays could refer to multiple people

OpenStudy (anonymous):

which means that f(x) = 2x

OpenStudy (anonymous):

So how many times is 2x more than x?

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

Indeed. So what's an other way of saying that something is 2 times more than something else?

OpenStudy (anonymous):

f(x)2 something like that ? or x+x

OpenStudy (anonymous):

Wel 2x = x+x but that was not my point. My point is, that 2x, is the "double" of x

OpenStudy (anonymous):

so the function maps x to it's double

OpenStudy (anonymous):

And that's really all you can say about it. Because x is a variable, and it depends on the value you want to "plug" into it.

OpenStudy (anonymous):

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OpenStudy (anonymous):

It's actually the other way around.

OpenStudy (anonymous):

But I think I understand your question now. IS it a function or a relation? Well, does each unique input correspond to exactly one output?

OpenStudy (anonymous):

ohh so x to 2x? is its a function ?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

wait so there is two inputs from the same place ? so its nt relation its a function

OpenStudy (anonymous):

Your input is x, your output is 2*(x), which is equal to (2*input)

OpenStudy (anonymous):

All you need to determine is something is a function is that each unique input has to be mapped to one and only one output

OpenStudy (anonymous):

aha now i see so the answer is its not a function?

OpenStudy (anonymous):

So obviously, that's not a problem here. But let me ask you something now. \[f(x) = \pm \sqrt{x^2}\] Is this a function?

OpenStudy (anonymous):

yes i guess

OpenStudy (anonymous):

And about your question, it is a function. Each input has exactly one output.

OpenStudy (anonymous):

But my question, is not a function

OpenStudy (anonymous):

because x is mapped to both +sqrt(x^2) and -sqrt(x^2)

OpenStudy (anonymous):

in order for it to be a function, it can only have one output for each input. This thing has two outputs for each input, so it's definitely not a function.

OpenStudy (anonymous):

oh yeah yeah i mixed up i did the opposite

OpenStudy (anonymous):

Do you understand now? :)

OpenStudy (anonymous):

yeah inputs has only 1 output

OpenStudy (anonymous):

yes thanxxx man :D i appreciate :)

OpenStudy (anonymous):

no problem :)

OpenStudy (anonymous):

In the case of the birthdays, it would not be a function if each person had two birthdays. This should make it clear!

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