Question

sigma

Answer 1

What?

Answer 2

\[\sum_{k=1}^{49}(k+1)^3-k^3\]
evaluate

Answer 3

no formular jus a series

Answer 4

That series is just saying when you plug in k = 1, 2, 3, 4....49 and add them up, there should be a formula for the series to make the calculation easier. It is possible to calculate every term.

Answer 5

\[2^3-1^3+3^3-2^3+4^3-3^3+...+50^3-49^3\]

Answer 6

it appears to be a telescoping series

Answer 7

does it mean numbers are cancelling out

Answer 8

i think the anwers is
\[-1^3+50^3\]

Answer 9

\[\sum_{k=1}^{49}(k+1)^3-k^3\]
\[\sum_{k=1}^{49}(k+1)^3-\sum_{k=1}^{49}k^3\]
\[\sum_{k=1+1}^{49+1}(k)^3-\sum_{k=1}^{49}k^3\]
\[\sum_{k=2}^{50}k^3-\sum_{k=1}^{49}k^3=50^3-1^3\]