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if 5^n=x,find
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log x/ log 5
the value of \[x^{-1/n}(\log_{5}x^{1/n}) \]
i change the question to show that it is 1/5
substitute 5^n for x and you should find your answer
x^1/n = 5 so your final answer = 1/5
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yes it shuld give 1/5
affirmative
yes i made it myself,i am certain
\[x^{-1/5}(1/n)\log_{5}x \] well we can invert both sides\[x^{-1/n}=1/5\], \[\log_{5}x=n \] so we have \[(1/5)(1/n)(n)\]
=1/5
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