Question

Let h(x) = 4 - 3 x^3. Compute h'( 3 ).



Use this to find the equation of the tangent line to the curve y = 4 - 3 x^3 at the point ( 3 , -77 ). The equation of this tangent line can be written in the form y = mx+b. Determine m and b.

Answer 1

could u calculate h'(x) ?

Answer 2

h'(x) = -6(x)^2
so h'(3)= - 6(3)^2 = -6*9 = -54
that is the slope of your line
m= -54
u have a point (3,-77)
can u find the equation of line ?

Answer 3

wait... how'd you get -6(x)^2?

Answer 4

what is the derivative of x^n ?

Answer 5

u started with derivatives ?

Answer 6

... idk what that is.. my professor taught this today.. but she has a strong accent and im so confused.

Answer 7

ok,
\(\huge \frac{d}{dx}x^n=n.x^{n-1}\)
remember this formula.
According to this can u tell me derivative of x^3 ??

Answer 8

is that ^^ making any sense ?

Answer 9

I never was told that formula.

Answer 10

so now u know..... can u tell me
\(\frac{d}{dx}x^3\)