Question

integrate (cos 2x- cos 2 b) / (cos x - cos b)

Answer 1

With respect to what?

Answer 2

x

Answer 3

that is\[\int{\cos(2x)-\cos(2b)\over\cos x-\cos b}dx\]?
because if those 2's were exponents this would be a lot easier

Answer 4

@Aparna2 I can't help you if you don't answer me

Answer 5

write cos2x as \(2cos^2 x -1\)
cos 2b as \(2cos^2 b-1\)
then u convert \(cos 2x-cos 2b \)
as
\(2(cos^2 x-cos^2 b)\)
now u can write that as
(cos x +cos b)(cos x -cos b)
and cancel out cosx -cos b

Answer 6

holy heck, so it turns out the same as if the 2's were exponents!
mind blown...

Answer 7

...except there's a 2 in front of the integral now

Answer 8

yup. to check: the final answer would be 2(x cos b + sin x ) +c