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Mathematics 16 Online
OpenStudy (anonymous):

simplify

OpenStudy (anonymous):

\[\frac{ 4x }{ 9 }+\frac{ x-10 }{ 9 }\]

OpenStudy (anonymous):

so easy tati

OpenStudy (anonymous):

LCM=9

hartnn (hartnn):

common denominator so \(\huge \frac{4x+x-10}{9}\)

hartnn (hartnn):

whats 4x+x ?

OpenStudy (anonymous):

thank i got it

OpenStudy (anonymous):

\[\frac{ 5x-10 }{ 9 }\] ?

OpenStudy (anonymous):

@hartnn

hartnn (hartnn):

yup, thats correct :)

OpenStudy (anonymous):

thank you can you help me with like 5 more ?

hartnn (hartnn):

only 5 ?

OpenStudy (anonymous):

yes

hartnn (hartnn):

whats next ?

OpenStudy (anonymous):

\[\frac{ t^{2}+6 }{ t-1 }-\frac{ 7 }{ t-1 }\]

hartnn (hartnn):

again common denominator, \(\frac{t^2+6-7}{t-1}\)

OpenStudy (anonymous):

sorry the 6 has a t next to it

hartnn (hartnn):

whats 6-7 ?

hartnn (hartnn):

so can u factor t^2+6t-7 ?

OpenStudy (anonymous):

umm yes ?

hartnn (hartnn):

then tell me the two factors....

OpenStudy (anonymous):

ik you can factors that .. wouldnt one of the numbers be negative

hartnn (hartnn):

tell me 2 numbers whose sum is 6 and product is -7 yes,one of them is negative.

OpenStudy (anonymous):

(t-6)(t+1) ??

hartnn (hartnn):

nice, its (t+7)(t-1) then cancel out t-1 from numerator and denominator what do u get finally ?

OpenStudy (anonymous):

(t+7)

hartnn (hartnn):

thats it. :)

OpenStudy (anonymous):

okay the next one \[\frac{ 3 }{ x }+\frac{ 13 }{ x-11 }\]

OpenStudy (anonymous):

wouldnt the top be 16

hartnn (hartnn):

nopes,its not the same denominator now.

hartnn (hartnn):

u need to cross multiply..... can u ?

OpenStudy (anonymous):

3x-33+13x

hartnn (hartnn):

yup,thats the correct numerator.... which will be 16x-33 and what will be denominator?

OpenStudy (anonymous):

uhhh i dont know i thought the denominator would cancel out cross we crossed multiplied

hartnn (hartnn):

nopes it would be \(\huge \frac{16x-33}{x(x-11)}\)

OpenStudy (anonymous):

ohh okay ... \[\frac{ 5 }{ 4x ^{2}y }-\frac{ y }{ 14xy }\]

OpenStudy (anonymous):

??

hartnn (hartnn):

sorry, i kinda lost connection :( tell me the LCM of 4x^y and 14xy ?

OpenStudy (anonymous):

oh okay it would be 2xy

hartnn (hartnn):

right, so can u solve that further ?

OpenStudy (anonymous):

what do you mean?

hartnn (hartnn):

ok, i'll write next step, see it that makes sense \(\huge \frac{5(7)}{28x^2y}-\frac{y(2x)}{28x^2y}\)

OpenStudy (anonymous):

ohh okay .. \[\frac{ 35 }{28x ^{2}y }-\frac{ 2xy }{ 28x ^{2} y}\]

OpenStudy (anonymous):

then combine the denominator

hartnn (hartnn):

but did u get how i got that ? yes,then combine denom.

OpenStudy (anonymous):

yea i saw you got that,

hartnn (hartnn):

so finally u get (35- 2xy)/(28x^2y) ok?

OpenStudy (anonymous):

\[\frac{ x ^{2}+2x }{12x+54 }-\frac{ 3x }{ 8x+36 }\]

OpenStudy (anonymous):

would i combine the like terms on the bottom & top

hartnn (hartnn):

nopes, first can u write 12x+54 as 6(2x+9) ??

OpenStudy (anonymous):

you can cause that would equal the original equation

hartnn (hartnn):

so how would u write 8x+36 ?

OpenStudy (anonymous):

8 doesn't go into 36 tho

OpenStudy (anonymous):

36 doesnt go into 8 i mean

hartnn (hartnn):

what about 4 ? 36 and 8 both go into 4.

OpenStudy (anonymous):

4(2x+9)

hartnn (hartnn):

right so u have \(\huge\frac{ x ^{2}+2x }{12x+54 }-\frac{ 3x }{ 8x+36 }=\frac{ x ^{2}+2x }{6(2x+9) }-\frac{ 3x }{ 4(2x+9) }\) can u figure out next step ?

OpenStudy (anonymous):

you would factor the top

hartnn (hartnn):

before that... \(\huge\frac{ x ^{2}+2x }{6(2x+9) }-\frac{ 3x }{ 4(2x+9) }=\frac{2( x ^{2}+2x) }{12(2x+9) }-\frac{ 4(3x) }{ 12(2x+9) }\) u see how i tried to make the denominator same ?

hartnn (hartnn):

sorry it would be 3 in the numerator of 2nd fraction 3(3x)

OpenStudy (anonymous):

i see it i see it it makes sense so then you would take away the denominator?

hartnn (hartnn):

take away ? since the denominator is common u combine the numerators. (2x^2+4x-9x)\(12(2x-9))

OpenStudy (anonymous):

yea thats what i meant

OpenStudy (anonymous):

would the answer be 2x^2-5x/(12(2x-9)

hartnn (hartnn):

yup, thats correct. (2x^2-5x)/(12(2x-9))

OpenStudy (anonymous):

awesome .. there is one more

hartnn (hartnn):

ok, ask.

OpenStudy (anonymous):

\[\frac{ 2 }{ x ^{2}8x+15 } +\frac{ 1 }{ x ^{2} +11x+30}\]

OpenStudy (anonymous):

x^2 + 8 **

hartnn (hartnn):

can u factor both the quadratic polynomials in denom. ?

OpenStudy (anonymous):

i dont think so, im not sure

hartnn (hartnn):

x^2+8x+15 = (x+5)(x+3) and x^2+11x+30=(x+5)(x+6) ok?

OpenStudy (anonymous):

ohhhhhh okay

OpenStudy (anonymous):

\[\frac{ 3 }{ (x+3)(x+6) } or \frac{ 2 }{ (x+3) }+\frac{ 1 }{ (x+6)}\]

hartnn (hartnn):

\(\large\frac{ 2 }{(x+5)(x+3)} +\frac{ 1 }{(x+5)(x+6)}=\frac{ 2(x+6) }{(x+6)(x+5)(x+3)} +\frac{ (x+3) }{(x+3)(x+5)(x+6)}\) the idea is to make the denominator same, so that u can combine numerator....

OpenStudy (anonymous):

oh okay

hartnn (hartnn):

so after combining numerators , u get 2x+12+x+3 = ?

OpenStudy (anonymous):

3x+15

hartnn (hartnn):

can u take out something common from that?

OpenStudy (anonymous):

5

hartnn (hartnn):

i would say 3 3(x+5)

OpenStudy (anonymous):

so thats the answer?

hartnn (hartnn):

the numerator's (x+5) cancels with denominator's (x+5) to give u \(\huge \frac{3}{(x+3)(x+6)}\)

OpenStudy (anonymous):

thank you soo much, you're amazing!

hartnn (hartnn):

welcome :) u too are awesome ;)

OpenStudy (anonymous):

thanks ^_^

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