Question

The point (3, 2) is 6sqrt(2) units away from the point (x, 8). Find the value of x

Answer 1

d^2 = (x2 - x1)^2 + (y2-y1)^2
6^2 * sqrt(2)^2 = (x - 3)^2 + (8-2)^2
36*2 = (x-3)^2 + 6^2
36*2 = (x-3)^2 + 36
36*2 - 36 = (x-3)^2 + 36 - 36
36 = (x-3)^2
6 = x-3
6 + 3 = x - 3 + 3
9 = x
x = 9

Answer 2

I have the answers and it says x=-3

Answer 3

I just dont know how to get it

Answer 4

Actually, my x = 9 works but so does x = -3 and I did skip something accidentally but I found it and it's that when I square rooted both sides

36 = (x-3)^2

I should have taken both the positive and negative possibilities.

sqrt(36) = +/- sqrt((x-3)^2)

so 6 = +(x-3) and 6 = -(x-3)

so x = 9 AND x = -3.

Answer 5

Oh i see now. Thats actually pretty easy, just didnt know where to start.

Answer 6

I should say "or" rather than "and".

Answer 7

Yes, well I'm glad you get it now. :)

Answer 8

Thank you =D

Answer 9

No problem!