Radium has a half-life of 1,620 years. In how many years will a 1 kg sample of radium decay and reduce to 0.125 kg of radium? 1,620 years 3,240 years 4,860 years 6,480 years
Please help me :(
hint: 0.125 = 1/8
The formula for half-life is:\[\frac{1}{2} N_0=N_0 e^{kt}\]Simplified that becomes: \[\frac{1}{2}=e^{kt}\] First you need to solve for k. There are two ways you can do this for a half-life problem. The simplest is if you know the formula:\[Half-life=1620=\frac{-ln(2)}{k}\]\[k=\frac{-ln(2)}{1620)}=-4.278686x10^{-4}\] The second method is just mathematically solving the half-life formula for k: \[\frac{1}{2}=e^{kt}\]\[\frac{1}{2}=e^{k(1620)}\]\[ln(\frac{1}{2}) =k(1620)\]\[k=\frac{ln(\frac{1}{2})}{1620}\]\[k=-4.278686x10^{-4}\] Now that you know k you can solve the equation for t:\[0.125kg=(1kg)(e^{(-4.278686x10^{-4})t)}\]\[t=\frac{ln(0.125)}{-4.278686x10^{-4}}=4860\space years\]
thank you , i thought it was c :)
= 1620*3.
do you know this question? According to the theory of evolution, amphibians evolved from ancient fish. Which of these would best validate the theory? record of history of a place a study published by a research scholar record of temperature changes of a place a study crediting the theory by many scientists
None of those are all that great, but historical data is probably best, followed by the study with numerous citations. The best validation for a theory is its predictive power and resistance to being falsified.
@CliffSedge: Was there a simpler method for the first question? I've always done those solving for k.
Yes. If there is 0.125kg remaining of the original 1kg, then there is 1/8 remaining. 1/8 = (1/2)^3
Ah...I didn't see that. Thanks :)
For half-life, you can start with final = original*(0.5)^n, n= number of times it was cut in half, so multiply that by the half-life time period.
correct^ its actually pretty simple after you learn it :)
I've always done it using the way I posted which is only slightly more work once you're familiar with it...habit I guess.
Still, it's important to know the general exponential function equation for different scenarios.
@Shane_B it's a tool that always works, but like the quadratic formula, sometimes it's overkill. Would you use QF for x^2-4=0?
Nope :)
My method is to not memorize formulas, but to always (if I can) derive the one I need based on the situation. If I can't derive it myself, then I go looking for the general formula.
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