Two organ pipes, open at one end but closed at the other, are each 1.25 m long. One is now lengthened by 1.80 cm . Find the frequency of the beat they produce when playing together in their fundamental.
Help guys! Please!
Obfiusly, we have to find the fundamentals first. Remember the formula?
|dw:1347491164176:dw| for fundamental resonance, L must be equal to 1/4 of lambda. From here, you can find lambda (and then frequency) of each pipe.
So, L is 5m?
No, no, you seem to missed the point. Here: 1/4 lambda =L lambda=4*L from this lambda, you can find frequency: lambda=v/f (v is speed of sound in air)
lambda = 5m frequency = 5/344 m = .0145 is that good so far?
actually, f=v/lambda :)
whoops. so 344 m/s / 5m = 68.8 what do i do now?
Yep, good. Now find the frequency of second pipe.
344m/s / .072 m = 4777.78
Correct. The result's quite surprising, because huge difference in length. Remember the definition of beat?
unfortunately, i don't
Okay, I'll be patiently teach you :) Beat is difference frequency. It occurs when two slightly different frequency played simultaneusly. Try pressing two neighboring piano button, you'll recognize it.
ok
Can you find the frequency of the beat now?
is the frequency just the difference of the two frequencies i found? so is it 4708.98?
Yeah, mathematically, you're correct. But practically, beat will only occur (or realized) if the frequencies are slightly different, more like 400 Hz and 402 Hz.
so, my answer is wrong then?
No, you're right. But the problem must be reconsidered. Maybe the unit of second pipe shouldn't be in cm, but in m.
I tried that and got -21.02 but the homework is still saying that i'm not getting the answer right???
21,2 Hz seems more plausible. But you're in the right track if you explain in your homework that beat doesn't really occur.
The homework is masteringphysics though, so I can't exactly say that through an online homework
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