Question

solve
(t^2+6t)/t-1 - (7)/t-1

Answer 1

factor out the numerator.. multiply both expressions by the LCD which is t-1 so you can not deal with fractions.. then solve for x.

Answer 2

\[\frac{ t ^{2}+6t }{ t-1 }-\frac{ 7 }{ t-1 }\]Is that the correct equation

Answer 3

er t

Answer 4

yes thats right

Answer 5

I would not do what nameless said. it over complicates the problem

Answer 6

since the both have the same denominaor already you can add the numerators

Answer 7

in this case subtract them

Answer 8

\[\frac{ t ^{2}+6t-7 }{ t-1 }\]

Answer 9

now when we factor we need to think about was numbers, when multiplied equal -7. we get -7, 1 and -1, 7.

Answer 10

then we look at these numbers and think what numbers when added will give us 6.

Answer 11

we should arrive at \[\frac{ (t+7)(t-1) }{ t-1 }\]

Answer 12

as you can see you can cancel off the t-1's and your left with t+7

Answer 13

Ahh that is a nice way to do that. Thanks for helping me as well :)

Answer 14

Do you understand? ur welcome @Nameless

Answer 15

yes i understand what you saying