Question

Find the slope-intercept equation that passes through (-1, 2) and is perpendicular to the line with the equation 6y - x = 12.

A. y = -1/6x + 11/6
B. y = 1/6x + 13/6
C. y = 6x + 8
D. y = -6x -4

Answer 1

for this you first need to get your equation into y = mx + b form. do you know how to do that?

Answer 2

so 6y = x + 12 now isolate the y by dividing both sides by 6.

Answer 3

so the equation of the line they give you is y = 1/6x + 2 right?

Answer 4

the perpendicular line has a slope that is m1 = -1/m2

Answer 5

whats m1 and m2 ?

Answer 6

m1 is the slope of the first line.. so -1/m2 is the slope of the second line.

Answer 7

so the slope is the negative reciprocal of the original slope.

Answer 8

so if your slope is 1/6 the slope of the perpendicular line would be -6 or -6/1 .. the negative reciprocal

Answer 9

so now you have the slope of the line 2.. you can plug in the points they give you into the point slope formula y - y1 = m(x-x1) to get the equation of the line you are looking for

Answer 10

do you understand?

Answer 11

yes i think so . let me try and work it out!

Answer 12

ok :) lemme know what u come up with.

Answer 13

i got y = -4x -4 ?

Answer 14

-6x since -6 is the slope.

Answer 15

-6(x + 1) + 2 = -6x - 6 + 2 = -6x - 4

Answer 16

oh i added 2 to the -6. oops :)

Answer 17

great! good luck :) medal my answer if it helped

Answer 18

i was planning on it! haha thank you (: