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find the limit and confirm your answer using the Sandwich Theorem as the lim x approaches positive and negative infinity 1-cos x/ x^2
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|dw:1347496945593:dw| follow me?
can you explain what you just did?
cosx is varing -1 to 1
its value is varing -1 to 1 dependent on x value
so -1<cosx<1 and if you take negative sign all parts then -1<-cosx<1
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and add each part 1 then 0<1-cosx<2 and devide each part as x^2 because x^2 is always positive, 0<(1-cosx)/x^2<2/x^2
finally take limitation x goes to infinity then you can get 0<lim[(1-cosx)/x^2<0
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