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Mathematics 14 Online
OpenStudy (anonymous):

find the limit and confirm your answer using the Sandwich Theorem as the lim x approaches positive and negative infinity 1-cos x/ x^2

OpenStudy (anonymous):

|dw:1347496945593:dw| follow me?

OpenStudy (anonymous):

can you explain what you just did?

OpenStudy (anonymous):

cosx is varing -1 to 1

OpenStudy (anonymous):

its value is varing -1 to 1 dependent on x value

OpenStudy (anonymous):

so -1<cosx<1 and if you take negative sign all parts then -1<-cosx<1

OpenStudy (anonymous):

and add each part 1 then 0<1-cosx<2 and devide each part as x^2 because x^2 is always positive, 0<(1-cosx)/x^2<2/x^2

OpenStudy (anonymous):

finally take limitation x goes to infinity then you can get 0<lim[(1-cosx)/x^2<0

OpenStudy (anonymous):

Thank you!

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