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Mathematics 6 Online
OpenStudy (anonymous):

Solve and show work for: y > or equal to |x - 1| - 2 be????

OpenStudy (firejay5):

Wow smart thinking

OpenStudy (anonymous):

;)

OpenStudy (anonymous):

I need to know also :)

OpenStudy (firejay5):

;) thanks man! :D

OpenStudy (anonymous):

@Chlorophyll

OpenStudy (anonymous):

A?

hero (hero):

@Firejay5, did you compute A yet?

OpenStudy (anonymous):

Could you help answer this?

OpenStudy (anonymous):

For me also. not just Fire :S

hero (hero):

y ≥ |x-1| -2 Add 2 to both sides to get y + 2 ≥ |x - 1| Take the inverse absolute value of both sides to get ± (y + 2) ≥ x - 1 Add 1 to both sides to get ± (y + 2) + 1 ≥ x

hero (hero):

@jiji501

OpenStudy (anonymous):

How would you graph it though?

hero (hero):

If you have to graph it, just leave it in the form given to you and use a graphing calculator to graph it

OpenStudy (anonymous):

Ughh, ok.

OpenStudy (anonymous):

1. Graph y = x 2. Shift the graph to the right 1 unit 3. Take only the positive segment, then take the negative segment make symmetry over x axis 4. Shift the whole graph down 2 units

OpenStudy (anonymous):

@Firejay5 does it answer your post, too?

OpenStudy (firejay5):

yea I guess

hero (hero):

Actually, if he followed your steps precisely @chlorophyll, he would not have the right graph. There are a couple of mistakes with them.

hero (hero):

For example, if he graphed y = x, he would have |dw:1347503678508:dw| to begin with. But let's assume he already knows to start with |dw:1347503738442:dw| Well, then you tell him to move it over one, then flip it over the x axis. If he did that, he would end up with |dw:1347503826640:dw|

OpenStudy (anonymous):

Your graph is wrong, because when you shift the down, the graph is still in V shape :(

hero (hero):

I know it is wrong. I was following YOUR steps. Don't you understand?

OpenStudy (anonymous):

NO, I don't think my graph wrong! Could you show me why???

hero (hero):

I already attempted to show you.

OpenStudy (anonymous):

Then show the CORRECT one :P

hero (hero):

I don't want to post the answer on here

hero (hero):

I know what it should look like however.

hero (hero):

I was just saying that he would not get the right answer using your provided steps.

hero (hero):

It was a good attempt though

OpenStudy (anonymous):

It's up to you! I just try to help the poster. I'm still thinking about the how to explain the region, as the matter of fact I'm not articulate type as you are :)

hero (hero):

I think it would be easier if you started by attempting to explain what y = |x| means and what it looks like, and then going from there.

OpenStudy (anonymous):

I don't think he has problem graphing y = x!

OpenStudy (anonymous):

When he's online, he'll surely ask more though!

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