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Find the limit for lim (sin4x)/(sin6x) x==>0
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gotta use \[ \large \lim_{x\to0}\frac{\sin x}{x}=1 \]
But how do I use that when I have 4x and 6x?
What are the steps to solving this? \[\lim_{x \rightarrow 0} \tan(6x)\div \sin(2x)\]
So I can find the limit
sorry. busy
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first multiply and divide by 1/x \[ \large \lim_{x\to0}\frac{\sin 4x}{\sin 6x}= \lim_{x\to0}\frac{\frac{\sin 4x}{x}}{\frac{\sin 6x}{x}} \]
then multiply and divide the numerator by 4 and by 6 the denominator
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