determine the type of boundary line and shading for the graph of the inequality -4x-y<-2 A.) Dashed line with shading on the side that includes the origin. B.) Solid line with shading on the side that does not include the origin. C.) Dashed line with shading on the side that does not include the origin. D.) Solid line with shading on the side that includes the origin.
hi.
can you help me?? :/
i can.
im like completely lost!
ok. it is allright. now, can you get the y on the other side of the inequality sign?
try adding y to both sides of the inequality.
no D:
okay
now, add the two to both sides
okay!
remember the only thing different about operating on a linear inequality and a linear equation is that if you multiply or divide the inequality by a negative number, you have to switch the inequality direction
so it switches ?
you should have something like this: y>-4x+2
yes
the inequality switches ONLY if you multiply or divide by a NEGATIVE number. we have not actually done that here, but i mention it because if you can solve linear equations, then you can solve inequalities as long as you remember the rule about neg numbers
oh okay...
good to know
ok. now, the line determined by y=-4x+2 is the boundary
ok
but do we use a dashed or solid line? hmmmmm....
dashed?
well, solid lines are used when the inequality contains an = sign. so yes, dashed is correct. fantastic. nicely done
yay!
now, the part you color in contains all the points where the y coordinate is greater than or 'above' the dashed line.
so the graph kinda cuts the paper into two pieces. One part you color and one part you dont
can you graph the line?
it will go downward from left to right because it has a negative slope and a y intercept of +2
did you graph the line?
yes
ok, now the area you want to color because of the y> part is above the graph
ok
so it is going to be on the top right side of the paper
right
ok, i think you are done. any other questions?
but is it with or without the origin ?
without the origin
ohhh ok! thanks
graphit and it will make sense'
take care
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