Question

Find an equation of the line satisfying the given conditions

passing through (2,-9) and perpendicular to the line 5y = -(2x/9) + 5

Answer 1

Find the slope m of 5y = -2x/9 + 5
by dividing both side for 5
Can you do it?

Answer 2

how will that get the equation?

Answer 3

first:get the derivative of your equation

Answer 4

just do whatever Chlorophyll told you.. :D..

Answer 5

can someone please give me the answer i honestly have no clue

Answer 6

1

Answer 7

-10/9

Answer 8

(-2x+45)/45

Answer 9

Divide 5 to the right side -(2x/9)
-> -(2x/45) + 1

Answer 10

Do you know slope m now?

Answer 11

m=1 ?

Answer 12

y = mx + b
Try again!

Answer 13

what is that? ^

Answer 14

maths is my worst subject i am very sorry

Answer 15

This is linear equation in slope- intercept form (m is slope, b is y intercept)
y = mx + b
y = -(2x/45) + 1
Now try to find slope m this time

Answer 16

how?

Answer 17

Matching to find what number in front of x, can you?

Answer 18

-2

Answer 19

No, the whole faction !

Answer 20

slope = -2/45 ?

Answer 21

There you go!

Answer 22

Now, can you find the slope of perpendicular line?

Answer 23

45/2 ?

Answer 24

now?

Answer 25

No, flip it 2/45

Answer 26

so is this the final answer? y = -(2x/45) + 1

Answer 27

NO, you use the given linear line to find slope of the perpendicular line!
=> m = 2/45

Answer 28

Now the slope and give point into Point Slope formula:
y - y1 = m ( x - x1)

Can you?

Answer 29

i have no clue now

Answer 30

given point (x1, y1) = (2, -9)