Question

\(\ \Huge 36=\log_{2}x, solve for x? \)

Answer 1

do you know how to change that into exponential form?

Answer 2

@Study23 ...yes or no?

Answer 3

2 to the what power equals 36?

Answer 4

\(\ \Huge 2^{x} =36, \mathsf{how do I find x?} \)

Answer 5

if \(\huge log_ab=c\)
then
\(\huge a^c=b\).
u see where have u done the mistake ?

Answer 6

you changed it wrong

Answer 7

\[\huge \log_{base} (power) = exponent\]

so for example you have \[\huge \log_2 4 = 2\]
this translates to \[\huge \log 2^2 = 4\]
got it?

Answer 8

So for this problem, it would be \(\ \Huge x = 2^{36} ? \)

Answer 9

yup, thats correct :)

Answer 10

So some really big number?

Answer 11

u wanted the exact value? then yes, very big number....else leave it in this form.

Answer 12

you can do it by hand too

Answer 13

Actually, x is not a really big number.

Answer 14

5 < x < 6

Answer 15

@hero ?

Answer 16

\(2^5 = 32\) and \(2^6 = 64\) therefore, \(5 < x< 6\)

Answer 17

hmmm....but,i got 2^36 as 68719476736

Answer 18

I thought the original problem was \(2^x = 36\)

Answer 19

Oh, no it wasn't...

Answer 20

But you posted something to that effect earlier.