A tugboat goes upstream 160 miles in 10 hours. The return trip downstream takes 5 hours. Find the speed of the tugboat without a current and the speed of the current.
Thank you
Let me know what you get for b and c
I got 16 for b and 32 for c
How is it possible that b < c when we need b - c to be positive?
I am not sure. honestly I have been stuck on this question for almost an hour.
Hint: use d = rt, where r = (b ± c) 160 = 10(b-c) 160 = 5(b+c) Solve the system
Try that and see what you get
I got c=16 and b=32. so the tugboat goes 32 mph and the speed of the current would be 16. Thank you for your help.
No, sorry, that still is not correct. I have no clue how you are going about solving this
I show you that 160 = 10(b-c) 160 = 5(b+c) The next step would be to divide both sides of the first equation by 10, and both sides of the second equation by 5 to get: 16 = b - c 32 = b + c However, we need to find b and c separately.
I am solving it by eliminating the c or b. Like I stated above, I have been at this equation for an hour just about, I am confused on how to solve for this. I am sorry for miss understanding you, I just do not get it.
I'm pretty sure you got 16 = b - c 32 = b + c in your initial steps. The problem is, we are not done yet.
We're not done until we isolate one of the variables and find a specific value for it
If you think about it, we have a system of equations here. And we can easily eliminate c by adding both equations together. If we do that we get 48 = 2b
so if 48=2b, we would divide both sides by 2?
Yes, but the important thing is that you understand how I got to 48 = 2b
you took 16=b-c 32=b+c and you added both sides together, so that is how you got 48=2b. 16+32=48 and b+b 1+1= 2 I have noticed you could not do this to c, because a negative plus a positive would eliminate the c all together.
Okay, so have you actually solved for b yet?
If so, what did you get?
b=24
Okay, so if b = 24, what is c?
c would equal 0 if we used this term by adding the equations together.
That was only to eliminate c so that we could solve for b. That doesn't mean c equals zero.
c could equal any number. The way you get zero is by taking whatever number you have and subtracting that same number to get zero. 10 - 10 = 0 16 - 16 = 0 4 - 4 =0 a - a = 0 b - b = 0 those are just examples, but they show that those are numbers that are subtracted to get zero. But of course 10 ≠ 0, 16 ≠ 0, 4 ≠ 0, a ≠ 0, b ≠ 0, and in this case c ≠ 0
would c=8 if we plugged 24 in an equation?
Actually, it is 8. My bad. Good job
Finally...you had me confused at certain points too
Thank you, you had me re think myself, because both sides gave me 8
so 24 would be the mph and 8 would be the current?
24 mph = speed of the boat 8 mph = speed of the current That's why I used b and c as variables of course
thank you for you help, I am glad we used it this way. you made it less confusing. :)
As a general rule the speed of the boat must be greater than the speed of the current. Otherwise, the boat would not get to its destination.
Okay. I will remember that.
Also another thing you need to remember is this: Upstream = boat against current = b - c downstream = both with current = b + c This is why the equations are setup as such Upstream: 160 = 10(b-c) Downstream: 160 = 5(b+c)
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