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Mathematics 21 Online
OpenStudy (anonymous):

At the end of a dock, high tide of 14 m is recorded at 9:00 a.m. Low tide of 6m is recorded at 3:00 p.m. A sinusoidal function can model the water depth versus time. HELP PLEASE!

OpenStudy (anonymous):

a) construct a model for the water depth using a cosine function, where time is measure in hours past high tide.

OpenStudy (anonymous):

and for sine.

OpenStudy (anonymous):

Here amplitude is 4m right?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

and the vertical shift is 10

OpenStudy (anonymous):

So, y=4cosx + 10

OpenStudy (anonymous):

what is the difference between 3:00 PM and 9:00 AM

OpenStudy (anonymous):

6 hour right?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

So, timeperiod = 12 hour

OpenStudy (anonymous):

360/12= 30?

OpenStudy (anonymous):

So, its y= 4 cos(30t)+10

OpenStudy (anonymous):

Yes, that's right and how do I write the equation for sine?

OpenStudy (anonymous):

Same, y=4 sin(30t)+10

OpenStudy (anonymous):

But the time difference is taken from different point

OpenStudy (anonymous):

From 12:00PM

OpenStudy (anonymous):

The correct answer is y=4sin[30(t-3)]+10 from the back of the book.

OpenStudy (anonymous):

Oh ya that can be

OpenStudy (anonymous):

How did they get " t-3 mhmh

OpenStudy (anonymous):

y=4 sin(30t-90)+10

OpenStudy (anonymous):

Since its maximum when t=0, sinx=1

OpenStudy (anonymous):

So, Sinx=sin90

OpenStudy (anonymous):

got it, thank you!

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