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Mathematics 4 Online
OpenStudy (anonymous):

Find the values of the 30th and 90th percentiles of the data. 129, 113, 200, 100, 105, 132, 100, 176, 146, 152 A. 30th percentile = 105; 90th percentile = 200 B. 30th percentile = 113; 90th percentile = 200 C. 30th percentile = 105; 90th percentile = 176 D. 30th percentile = 113; 90th percentile = 176

OpenStudy (amistre64):

how many numbers are there?

OpenStudy (anonymous):

10

OpenStudy (amistre64):

and 30% of 10 = 3, but that is a whole number so we want the average of the 3rd and 4th positions once the numbers are placed in order from small to big

OpenStudy (amistre64):

for the 90th percentile; 90% of 10 is what?

OpenStudy (anonymous):

9

OpenStudy (amistre64):

and since 9 is a whole number, we want to average the 9th and 10th positions to determine the 90th percentile

OpenStudy (anonymous):

100, 100, 105, 113, 129, 132, 146, 152, 176, 200

OpenStudy (amistre64):

hmm, they seem to be using a different definition for percentile

OpenStudy (anonymous):

I got the average as 188 for 90th percentile

OpenStudy (amistre64):

assume we wanted the 50th percentile, also known as the median. 50% of 10 = 5; according to this problem, that would mean we would have to decide between 129 and 132 for the median; which is absurd.

OpenStudy (amistre64):

the choices dont reflect the correct procedures ...

OpenStudy (amistre64):

if i were to take a guess; and this is a 50/50 scenario, id assume they are wanting "c"

OpenStudy (anonymous):

I thought the same but when i guessed C i got it wrong =/

OpenStudy (amistre64):

try b?

OpenStudy (anonymous):

ok thanks I'll try B and then ask my teacher for credit if I get it wrong

OpenStudy (amistre64):

i just dont see a "correct" option ...

OpenStudy (amistre64):

good luck ;)

OpenStudy (anonymous):

thanks :D

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