Find the values of the 30th and 90th percentiles of the data. 129, 113, 200, 100, 105, 132, 100, 176, 146, 152 A. 30th percentile = 105; 90th percentile = 200 B. 30th percentile = 113; 90th percentile = 200 C. 30th percentile = 105; 90th percentile = 176 D. 30th percentile = 113; 90th percentile = 176
how many numbers are there?
10
and 30% of 10 = 3, but that is a whole number so we want the average of the 3rd and 4th positions once the numbers are placed in order from small to big
for the 90th percentile; 90% of 10 is what?
9
and since 9 is a whole number, we want to average the 9th and 10th positions to determine the 90th percentile
100, 100, 105, 113, 129, 132, 146, 152, 176, 200
hmm, they seem to be using a different definition for percentile
I got the average as 188 for 90th percentile
assume we wanted the 50th percentile, also known as the median. 50% of 10 = 5; according to this problem, that would mean we would have to decide between 129 and 132 for the median; which is absurd.
the choices dont reflect the correct procedures ...
if i were to take a guess; and this is a 50/50 scenario, id assume they are wanting "c"
I thought the same but when i guessed C i got it wrong =/
try b?
ok thanks I'll try B and then ask my teacher for credit if I get it wrong
i just dont see a "correct" option ...
good luck ;)
thanks :D
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