Given: In ∆ACB, c2 = a2 + b2. Prove: ∆ACB is a right angle. Complete the flow chart proof with missing reasons to prove that ∆ACB is a right angle. Which pair of reasons correctly completes this proof? Answers Reason #1 - Transitive Property of Equality Reason #2 - SSS Postulate Reason #1 - Reflexive Property of Equality Reason #2 - SAS Postulate Reason #1 - Transitive Property of Equality Reason #2 - SAS Postulate Reason #1 - Reflexive Property of Equality Reason #2 - SSS Postulate
f^2 = a^2+b^2 = c^2 => f^2 = c^2 whats above property ?
is it transitive/reflexive ?
???
didnt get either !!!
I'm not the only one?...good
check this and see if you can tell which property it is, http://www.mathwords.com/e/equation_rules.htm
Reflexive?
reflexive says, a=a which property is similar to below : f^2 = a^2+b^2 = c^2 => f^2 = c^2
isnt it like, If a = b and b = c then a = c. ?
Transitive Property
I should of gone with my gut.
finally ! thats right :)
we need to check what congruence postulate it is
I think it's SSS.
thats right! we are given two sides are congruent already, and we have just proven the third side f is also congruent. so its SSS you're Awesome :)
No you are!
lol okiee
Last question...yay
okay lets do...
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