Solve the system of the linear equation and interpret your solution geometrically 2x+y+2z-4=0 x-y-z-2=0 x+2y-6z-12=o. I have solved so many, am finding this one tricky, we use the elimination method to eliminate one of the variables..
no. 3 - no. 2 gives -3y + 5z + 10 = 0 no. 1 - 2* no 2 gives 3y + 4z = 0 adding the above 9z = -10 z = -10/9 - can you continue with this (i'm tired!!!)
let me solve ill get back to you very soon.
ok - the -10/9 is correct - i checked it out on my calculator
check no3-no 2 u made a mistake with the sign
lol - sorry - although i put 3 - 2 - did 2 - 3 so it is correct
which should i do?
2 - 3 is ok
2-3 after which i will do 1-2 rty?
now you you could plug z = -10/9 into equations 1 and 2 and solve for x and y
cwrw238 has correct value for z. This problem does not have pretty answers. But you are on track with cwrw238.
did you say 1-2? for the second one
thanks radar?
am confused????
i did 2-3 i got -3y+5z+10=0 what should i do next???
no i multiplied no 2 by 2 because no 1 has 2x in it so no 2 becomes 2x - 2y - 2z - 4 = 0 im afraid i didn't show this step then no 1 - this equation gave 3y + 4z = 0
-3y+5z+10=0 is correct now add 3y + 4z = 0 (derived above) to get an equation in z
good i now have the two equations so i should add them up right?
yes add them
yeah z= -10/9
right now you can plug z into, i suggest, no 1 and no 2 equations to give 2 equations in x and y
for the first one 2x+y-56/9=0
and for the second one x-y-8/9=0
yes
yeah so whats next?
well solve these 2 equations by elimination adding them will eliminate y ( as they contain y and -y)
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