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Find the quotient of 6(cos(11pi/6) + i sin(11pi/6) divided by ((cos3pi/2) + i sin (3pi/2)) The quotient is 3 + i 3 sqroot(3).?
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\[\frac{6(\cos(11\pi/6) + i \sin(11\pi/6)}{(\cos3\pi/2) + i \sin (3\pi/2)} \cdot \frac{(\cos3\pi/2) - i \sin (3\pi/2)}{(\cos3\pi/2) - i \sin (3\pi/2)}\]
This is the tricky way, convert it into polar form, and convert it back into rectangular after division. \[r(\cos(x)+isin(x))=r(e^{ix})\]
\[6(\cos(11 \pi/6)+isin(11 \pi/6))=6e^{i(11\pi/6)}\] \[(\cos(3 \pi/2)+isin(3 \pi/2))=e^{i(3\pi/2)}\]
And use\[\frac{a^m}{a^n}=a^{m-n}\]
So division now turns into subtraction- much less messy!
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