Solve the triangle. B = 73°, b = 15, c = 8
C = 35.9°, A = 71.3°, a ≈ 15.2 C = 30.7°, A = 76.3°, a ≈ 15.2 C = 30.7°, A = 76.3°, a ≈ 21.3 Cannot be solved
@Traxter
I'm sure you can set up an equation using the Sine rule now.
a/sina=b/sin73=8/sinC
You know what b is as well, substitute this in and then use the last 2 equations to find the angle C.
a/sina=15/sin73=8/sinC
Yes, so use the second 2 equations to find what C is.
sinC= 15sin73/8sin? i always have trouble with this part.
You have: \[\frac{15}{sin73}=\frac{8}{sinC}\] I'll try another path of thought that may make more sense to you. Divide both sides by 8 to get: \[\frac{15}{8sin73}=\frac{1}{sinC}\] Then flip the fractions round to get: \[sinC=\frac{8sin73}{15}\]
and then when i put it into wolf?
Apply sin^-1 to the right hand side to find the value of C. You should be able to write this now.
(8sin73/15)sin^-1 ??
No. It will be sin^-1((8sin73)/15). Can you see why?
Nope. You should be looking where it says conversion from radians to degrees.
30.67. yet thats not an option
oh i have to round!
well then i know its either one of these... C = 30.7°, A = 76.3°, a ≈ 15.2 C = 30.7°, A = 76.3°, a ≈ 21.3
Yep, so you can now find the size of angle A using the interior angle sum formula and then use the Sine rule again to find the size of angle a.
im sorry, i know weve done this like 2 times before already, but i still cant remember how to do that.
|dw:1347560664722:dw| I know you can set up the Sine rule using those sides to find the length of side a.
do i add 15+8 and subtract that from 73?
No, why would you do that?
idk, im loosing my mind!
Use the sine rule: |dw:1347560911885:dw| Does that help?
a/sinA=15/sinB=8/sinC ?
Yes, but you know what angles A, B and C are.
|dw:1347561027885:dw|
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