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Write the equation of the quadratic function with roots -1 and -7 and a vertex at (-4, 7)
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Roots at -1 and -7 so will have the form: \[y=a(x+1)(x+7)\] Substitute x=-4, y=7 to find a. Can you have a go?
\[y=a(x+1)(x+7)\] So that when you set y=0 (i.e. on the x-axis), x satisfies \[0=a(x+1)(x+7)\] when it is equal to -1 or -7
7=a(-4+1)(-4+7)
Yep, so: \[7=a\times(-3)\times(3)\] \[7=-9a\] \[a=\frac{-7}{9}\] Now do you see what the equation will be with this value of a?
y=7(x+1)(x=7) ?
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@Traxter
Not quite, if you substitue a=-7/9 into the equation I wrote before: \[y=a(x+1)(x+7)\] Then you will have: \[y=\frac{-7}{9}(x+1)(x+7)\] Agree?
yes!!
thank youuuuuuuu
and @henpen
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