what is the probability of the sum of two die will be greater than 8, given that the first is 6
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jimthompson5910 (jim_thompson5910):
The first die is 6, so you only need to focus on the second die
jimthompson5910 (jim_thompson5910):
Rolling a 1 through 6, which of these numbers will add to 6 and give us a result that is larger than 8?
OpenStudy (anonymous):
Can u please solve the whole sum?
jimthompson5910 (jim_thompson5910):
Does 1 work?
OpenStudy (anonymous):
Yes
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jimthompson5910 (jim_thompson5910):
So if the first die is 6 and the second die is 1, it will work?
OpenStudy (anonymous):
But the total should be greater than 8
jimthompson5910 (jim_thompson5910):
So 1 doesn't work
OpenStudy (anonymous):
Yes it doesnt
jimthompson5910 (jim_thompson5910):
What about 2?
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OpenStudy (anonymous):
No it says greater than 8 so should be numbers after two
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
What is the probability of rolling a 3, 4, 5, or 6?
OpenStudy (anonymous):
(1/6) X 4
jimthompson5910 (jim_thompson5910):
simplify and reduce that
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OpenStudy (anonymous):
2/3
jimthompson5910 (jim_thompson5910):
you got it
OpenStudy (anonymous):
Thats the answer?
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
Oh.. Thanks! One more doubt
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OpenStudy (anonymous):
A die is rigged so that the probabilities of obtaining the different faces are proportional to the number on the faces (eg: a five is five times more likely to be rolled than one) find: the probability of obtaining a 6.
jimthompson5910 (jim_thompson5910):
what did you get
OpenStudy (anonymous):
1
jimthompson5910 (jim_thompson5910):
1 means 100% certainty
jimthompson5910 (jim_thompson5910):
so are you always going to roll a 6?
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OpenStudy (anonymous):
I know its wrong but how do you do it?
jimthompson5910 (jim_thompson5910):
try it again, your answer should be between 0 and 1
OpenStudy (anonymous):
Cant understnd
jimthompson5910 (jim_thompson5910):
do you have your book with you?
OpenStudy (anonymous):
Yes
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jimthompson5910 (jim_thompson5910):
did you read the section on probability?
OpenStudy (anonymous):
I did
jimthompson5910 (jim_thompson5910):
then you would know that all probabilities are between 0 and 1
OpenStudy (anonymous):
I know it but the question says that a five is five times more likely to be rolled than one
OpenStudy (anonymous):
So if u go by that assumption then it should be 1/6 X 6
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jimthompson5910 (jim_thompson5910):
no, if 6 is six times more likely than 1, then 1 is still a possible outcome
OpenStudy (anonymous):
So how do i do it
jimthompson5910 (jim_thompson5910):
If 2 is twice as likely as 1, then
P(X = 1) = k
P(X = 2) = 2k
jimthompson5910 (jim_thompson5910):
Extend this out and add up all the probabilities. They should add to 1
k+2k+3k+4k+5k+6k = 1
OpenStudy (anonymous):
Ok.. Then
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OpenStudy (anonymous):
Oh so 1/7X 6
OpenStudy (anonymous):
No 1/21X6
OpenStudy (anonymous):
Is it like that?
jimthompson5910 (jim_thompson5910):
simplify and reduce
OpenStudy (anonymous):
2/7
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