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Mathematics 19 Online
OpenStudy (anonymous):

what is the probability of the sum of two die will be greater than 8, given that the first is 6

jimthompson5910 (jim_thompson5910):

The first die is 6, so you only need to focus on the second die

jimthompson5910 (jim_thompson5910):

Rolling a 1 through 6, which of these numbers will add to 6 and give us a result that is larger than 8?

OpenStudy (anonymous):

Can u please solve the whole sum?

jimthompson5910 (jim_thompson5910):

Does 1 work?

OpenStudy (anonymous):

Yes

jimthompson5910 (jim_thompson5910):

So if the first die is 6 and the second die is 1, it will work?

OpenStudy (anonymous):

But the total should be greater than 8

jimthompson5910 (jim_thompson5910):

So 1 doesn't work

OpenStudy (anonymous):

Yes it doesnt

jimthompson5910 (jim_thompson5910):

What about 2?

OpenStudy (anonymous):

No it says greater than 8 so should be numbers after two

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

What is the probability of rolling a 3, 4, 5, or 6?

OpenStudy (anonymous):

(1/6) X 4

jimthompson5910 (jim_thompson5910):

simplify and reduce that

OpenStudy (anonymous):

2/3

jimthompson5910 (jim_thompson5910):

you got it

OpenStudy (anonymous):

Thats the answer?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

Oh.. Thanks! One more doubt

OpenStudy (anonymous):

A die is rigged so that the probabilities of obtaining the different faces are proportional to the number on the faces (eg: a five is five times more likely to be rolled than one) find: the probability of obtaining a 6.

jimthompson5910 (jim_thompson5910):

what did you get

OpenStudy (anonymous):

1

jimthompson5910 (jim_thompson5910):

1 means 100% certainty

jimthompson5910 (jim_thompson5910):

so are you always going to roll a 6?

OpenStudy (anonymous):

I know its wrong but how do you do it?

jimthompson5910 (jim_thompson5910):

try it again, your answer should be between 0 and 1

OpenStudy (anonymous):

Cant understnd

jimthompson5910 (jim_thompson5910):

do you have your book with you?

OpenStudy (anonymous):

Yes

jimthompson5910 (jim_thompson5910):

did you read the section on probability?

OpenStudy (anonymous):

I did

jimthompson5910 (jim_thompson5910):

then you would know that all probabilities are between 0 and 1

OpenStudy (anonymous):

I know it but the question says that a five is five times more likely to be rolled than one

OpenStudy (anonymous):

So if u go by that assumption then it should be 1/6 X 6

jimthompson5910 (jim_thompson5910):

no, if 6 is six times more likely than 1, then 1 is still a possible outcome

OpenStudy (anonymous):

So how do i do it

jimthompson5910 (jim_thompson5910):

If 2 is twice as likely as 1, then P(X = 1) = k P(X = 2) = 2k

jimthompson5910 (jim_thompson5910):

Extend this out and add up all the probabilities. They should add to 1 k+2k+3k+4k+5k+6k = 1

OpenStudy (anonymous):

Ok.. Then

OpenStudy (anonymous):

Oh so 1/7X 6

OpenStudy (anonymous):

No 1/21X6

OpenStudy (anonymous):

Is it like that?

jimthompson5910 (jim_thompson5910):

simplify and reduce

OpenStudy (anonymous):

2/7

jimthompson5910 (jim_thompson5910):

that's correct

OpenStudy (anonymous):

Thanks

jimthompson5910 (jim_thompson5910):

yw

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