i have ,7,7,7,7,7,7,7,7,7 5,5,5,5,5,5,5,5 3,3,3,3,3,3,3,3 1,1,1,1,1,1,1,1 Using 10 numbers exactly. How do i total exactly 37
7a+5b+3c+d=37 a+b+c+d=10
And you have some extra restrictions, like the amount a < some amount and they are all natural numbers. You can solve this mathematically but probably you just want to try just plugging in some numbers.
Forgive an old man but in layman's terms can you assist my great grandson in plain English. I left full time education a very long time ago.
My point is that it can be solved mathematically, there are ways to do it, but it's not well known. Just try out various combinations, like I am doing right now :)
I have been trying all evening
I can get to 37 with 9 figure combinations and 11 figure combinations easily. But not 10 figures and my old brain tends to shut down at this time of night
Yep. It might not be possible
I'll try to work it out mathematically now, tired of trying xD. Not sure if I'll be able to solve it though
Let's see what I have so far: \[A,B,C,D \in N\]\[A \le 9 \]\[B,C,D \le 8\]\[7A + 5B + 3C + D = 37\]\[A+B+C+D=10\] \[6A+4B+2C = 27\]
\[6A = 27 -4B-2C\]\[A=\frac{27-4B-2C}{6}\]\[A=4.5 -\frac{2}{3}B - \frac{1}{3}C\]
I'm not sure where to go from here, I can create a whole set of possible equations, but it would take me ages to check
There is probably a better way to solve this :D
You can't solve this any combination of ten odd numbers brings out an even number as a result.
\[10(2n+1) = 20n + 10\] Sorry, I had a mistake there
in fact we can generalize it to any combination of an even number of odd numbers has an even number
Exactly xcrypt but thanks for working on it any way. I guess the answer he will give is " The answer is it cannot be done" Thank you
that's an evil question :D
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