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(x^2 + 3x + 1)(x^2 + x + 2) I got: X^4+3X^4+2X^4 is that right?
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no. you have to do this in steps. If we call (x^2 + 3x + 1) A that is A= (x^2 + 3x + 1) (for ease of typing) the problem is A*(x^2 + x + 2) distribute the A (multiply every term inside the parens by A) now replace A with its "real" meaning: (x^2 + 3x + 1) now distribute again then "collect like terms" x^4 terms, x^3 terms, x^2 terms and so on
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