Question

Solve for h: 2πrh + 2πr^2 = S

Answer 1

@Hero

Answer 2

Did you see my reponse to the previous question you posted?

Answer 3

Let me check it.

Answer 4

Anyways for this problem, subtract \(2πr^2\) from both sides. Let me know what you get afterwards.

Answer 5

2πrh=S-2πr^2

Answer 6

?

Answer 7

right now solve for h

Answer 8

Okay, good. Now divide both sides by \(2πr\). Let me know what you get

Answer 9

@zzr0ck3r, he has to understand the process first. saying "now solve for h" probably means nothing to him

Answer 10

yeah, im on te phone. I noticed that after I said it....

Answer 11

h=S- (I don't know what goes next becuase I'm left with the exponent by itself.)

Answer 12

Hint: You will be left with a fraction on the right side after dividing both sides by \(2πr\)

Answer 13

Your left side looks good so far.

Answer 14

Yeah but I get... \[\frac{ 2πr^2 }{ 2πr }\]

Answer 15

What happened to the S ?

Answer 16

That doesn't disappear

Answer 17

S-\[\frac{ 2πr^2 }{ 2πr}-S\]

Answer 18

You have to divide the entire right side by \(2πr\), not just \(2πr^2\)

Answer 19

ok

Answer 20

\[\frac{ S-2πr^2 }{ 2πr}\]

Answer 21

\[h = \frac{S - 2\pi r^2}{2 \pi r}\]

Answer 22

Good job

Answer 23

Thanks @Hero

Answer 24

Do you want to discuss the other question?

Answer 25

Yeah.

Answer 26

A=2πpw

Answer 27

I pinged you to the question