Question

Write the equation of the line with a slope of -1/3 and passing through the point (6, -4).

Answer 1

Hint:

Point-Slope form:
y - y1 = m(x - x1)
m = slope

Then convert to slope-intercept form:
y = mx + b

Answer 2

Does that help? Or would you like me to go over the steps?

Answer 3

Go over steps please!

Answer 4

Okay (:
You have a point and the slope so you can use the Point-Slope form. Fill in the x1 and y1 with the corresponding values and remember m = slope:

y - y1 = m(x - x1)

y - (-4) = -1/3(x - 6)

y + 4 = -1/3(x - 6)

Do you undertsand so far?

Answer 5

Yeah somewhat

Answer 6

do i solve y + 4 = -1/3(x - 6)?

Answer 7

Yes, first distribute the -1/3.

By the way, the x1 and y1 simply mark where you put the x- and y-values from the point.
(x, y) (6, -4)
Also, when you have two - signs you change them into +

Answer 8

y = -1/3x +2 ?

Answer 9

What happened to the + 4 on the left side of the equation?

Answer 10

You have everyting else right though...
y + 4 = -1/3x + 2
Now subtract 4 from both sides of the equation.

Answer 11

We want to change this into y=mx+b form so we need to get the y alone.