Question

gymnasium is 17 m high. By what percent is the air pressure at the floor greater than the air pressure at the ceiling.

I know that pgh is the difference but I have no idea what p are for bottom or top.Please show every single step and explain.

Answer 1

did you mean you don't know p or rho at the bottom.

Answer 2

Can you solve it for me

Answer 3

I am totally confused

Answer 4

?

Answer 5

I guess we need to know the pressure either at ceil or bottom. Any suggestion?

Answer 6

Pressure at bottom is the same as sea level

Answer 7

101,300 pa

Answer 8

then you get your answer
%difference=delta p/(p+delta p)

Answer 9

?

Answer 10

Can you show what you mean

Answer 11

\[%difference=\frac{ \Delta p }{ p_0 + \Delta p }\]
\[\Delta p=\rho g h\]

Answer 12

\[=\frac{ \Delta p }{ p_0 - \Delta p}\]

Answer 13

what are the numbers

Answer 14

what p should I put

Answer 15

rho aren't known in the problem?

Answer 16

Doesnt the rho on top differ from the bottom

Answer 17

Which rho should I put in

Answer 18

not really, for air, the rho is almost the same. It only differ if height difference is VERY high.

Answer 19

what do you get for final answer

Answer 20

what is rho of air?

Answer 21

1225 kg/m3 I guess?

Answer 22

I don't remember too, just google it. And i think 1225 kg/m3 is too dense for air.

Answer 23

1.225 I mean

Answer 24

got the right answee thanks

Answer 25

Yes, assume that's the density (cz air density varies with many factor, like temperature, height)