Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (lgbasallote):

How many ways can you arrange four people in a row of four seats? is this 4P4?

OpenStudy (anonymous):

No, its 4!

OpenStudy (anonymous):

4!= 4*3*2*1

OpenStudy (anonymous):

There is only one way

OpenStudy (anonymous):

But If u are asking for different arrangement then its 4!

OpenStudy (lgbasallote):

\[4 P 4 = \frac{4!}{(4-4)!} \implies \frac {4!}{0!} \implies 4!\] @GOODMAN

OpenStudy (anonymous):

So why go through all the trouble?

OpenStudy (anonymous):

Yep, \(_4P_4\) is correct.

OpenStudy (lgbasallote):

because of this next question im about to ask

OpenStudy (lgbasallote):

what about for arranging 4 people in 5 seats? is that 5P4? and arranging 5 people in 4 seats is also 5P4?

OpenStudy (anonymous):

Actually both will be 5!

OpenStudy (anonymous):

For first case it would be 5*4!=5! For second case it would be 5*4*3*2 = 5!

OpenStudy (anonymous):

If u are taking about arrangement

OpenStudy (lgbasallote):

....so they are both 5P4?

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

I think so

OpenStudy (anonymous):

Yes to both responses. To check we can show that: 4 people in 5 seats: We can always choose a single person whom is not in a seat, and there are 5 ways to do this, while the remaining 4 get a seat, thus: \(5\cdot_4P_4= _5P_4\), while for the latter, we have, simply \(_5P_4\) as the definition of "permute".

OpenStudy (lgbasallote):

i think im getting the hang of this

OpenStudy (anonymous):

Sounds good

OpenStudy (karatechopper):

So...like 16?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!