How to simplify ((1/x)-(1/3)) / (x-3) ?
\[\frac{ \frac{ 1 }{ x } - \frac{ 1 }{ 3 } }{ x-3 }\]
-1/3x
But can I see the steps @jk_16
here is the idea: (a/b)-(c/d) = (-b c+a d)/(b d)
do that for the top part..then do it again in the step when you divide by x-3
Why divide that by (bd)?
@jk_16
you multiply the denominator
the denominator is (x-3) though why (bd) ?
you have a choice you can multiply top and bottom by \(3x\) to clear the fractions, or you can actually do the addition in the numerator and then simplify the compound fraction
\[\frac{ \frac{ 1 }{ x } - \frac{ 1 }{ 3 } }{ x-3 }=\frac{\frac{3-x}{3x}}{x-3}=\frac{3-x}{3x}\times \frac{1}{x-3}\] \[=\frac{1}{3x}\times \frac{3-x}{x-3}\] and since \(\frac{3-x}{x-3}=-1\) you are left with \(-\frac{1}{3x}\)
How is it equal to -1? @satellite73
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