do that for the top part..then do it again in the step when you divide by x-3
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OpenStudy (3psilon):
Why divide that by (bd)?
OpenStudy (3psilon):
@jk_16
OpenStudy (anonymous):
you multiply the denominator
OpenStudy (3psilon):
the denominator is (x-3) though why (bd) ?
OpenStudy (anonymous):
you have a choice
you can multiply top and bottom by \(3x\) to clear the fractions, or you can actually do the addition in the numerator and then simplify the compound fraction
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OpenStudy (anonymous):
\[\frac{ \frac{ 1 }{ x } - \frac{ 1 }{ 3 } }{ x-3 }=\frac{\frac{3-x}{3x}}{x-3}=\frac{3-x}{3x}\times \frac{1}{x-3}\]
\[=\frac{1}{3x}\times \frac{3-x}{x-3}\] and since \(\frac{3-x}{x-3}=-1\) you are left with \(-\frac{1}{3x}\)