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A sample of NO2(g) is initially placed in a 2.50-L reaction vessel at 300°C. If the half-life and the rate constant at 300°C are 33 seconds and 0.54 M-1 s-1, respectively, how many moles of NO2 were in the original sample?
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You have to find the density of NO2 at 300°C. You will get something like (g/cm^3) = (g/ml) Convert the (g/ml) to (g/L) Multiple by 2.5 L. Then you will have the original sample.
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