Question

use a rational exponent to write sq.rt x??

Answer 1

Hint: Note that a^(1/3) = cube root of a

Answer 2

I am so lost???

Answer 3

x^-1/n ?????

Answer 4

You have the hang of it. Just adjust lose the -ve and replace the n with 2

Answer 5

x^ 1/2 ??

Answer 6

\[x^{\frac{p}{q}}\] \(p\) is the power, \(q\) is the root for example
\[x^{\frac{2}{3}}\] means \[\sqrt[3]{x^2}\]

Answer 7

You're right, but make sure you understand what @satellite73 has said.

Answer 8

and \(\sqrt[5]{x^2}=x^{\frac{2}{5}}\)

Answer 9

wish I knew it as well as you two.

Answer 10

yes, \(\sqrt{x}=\sqrt[2]{x^1}=x^{\frac{1}{2}}\)

Answer 11

that is why you are doing homework. this is simply notation, no one is born knowing it or "good" at it, you only need to practice

Answer 12

thanks :)

Answer 13

\[\sqrt{x}=x^{1/2}\]
\[\sqrt[4]{x}=x^{1/4}\]
\[\sqrt[3]{x^{2}}=x^{2/3}\]

Answer 14

\[x^{1/5}\] what expression does this equal???

Answer 15

\[\sqrt[5]{x

Answer 16

\[\sqrt[5]{x^{1}}\]

Answer 17

oh heck that didnt comeout right.

Answer 18

that is not one of the choices??

Answer 19

the choices are 4 or 5sq.rt.x or 1/5 or 1/9

Answer 20

plus 4 others???

Answer 21

\[\sqrt[5]{x^{1}}=\sqrt[5]{x}\]

Answer 22

5sq.rt.x

Answer 23

ok, that is what I was going for but was not sure. tytytyty

Answer 24

\[\sqrt[b]{x^{a}}=x^{a/b}\]